Steps for Completing the Square View solution steps Steps Using the Quadratic Formula y = { x }^ { 2 } 3x2 y = x 2 − 3 x 2 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side x^ {2}3x2=y x 2 − 3 x 2 = ySolved by pluggable solver Completing the Square to Get a Quadratic into Vertex Form Start with the given equation Subtract from both sidesGraph{y<(x^23x) 105, 95, 48, 52} First, we know it will look like an upwardfacing parabola because of the first term in the function x^2 with a coefficient of positive one Next we can determine that the graph will be shaded everywhere below the parabola, and the parabola will be a dotted line because of the <

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Y x2+3x+2 graph-Answer by jim_thompson5910() (Show Source) You can put this solution on YOUR website!In this video, I show you step by step how to find all the important points for sketching a parabola for the function y = x^2 3x 5 by converting a quadr



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Simple and best practice solution for y=x^23x10 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, soHow do you graph y=x2Video instruction on how to graph the equation y=x2 how do you graph y=x2Video instruction on how to graph the equation y=x2Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes
, We know that X=x1, so forGraph y=x^23x2 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabolaTo find the yintercept, plug in x=0 Lets find the value of y when Start with the given polynomial Plug in Raise 0 to the second power to get 0 Multiply 3 by 0 to get 0
👍 Correct answer to the question Determine whether each point lies on the graph of the equation y = x^2– 3x 2 (a) (2,0) Yes, the point is on the graph O No, the point is not on the graph (6) (2,8) O Yes, the point is on the graph O No, eeduanswerscomY = x^2 3x 5 y = 4x 1 Seth's solution y = x^2 3x 5 y = 4x 1 x^2 3x 5 = 4x 1 x^2 x 6 = 0 (x 3)(x 2) = 0 x = 3 and x = 2 The graphs intersect at() and (3,0) Is Seth's solution correct?Draw the graph of y = 2x^2 – 3x – 5 and hence solve 2x^2 – 4x – 6 = 0 y = 2x^2 – 3x – 5 asked in Algebra by Darshee ( 491k points) algebra



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Simple and best practice solution for Y=x^23x4 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, soThe equation is now solved x^ {2}3x2=y Swap sides so that all variable terms are on the left hand side x^ {2}3x=y2 Subtract 2 from both sides x^ {2}3x\left (\frac {3} {2}\right)^ {2}=y2\left (\frac {3} {2}\right)^ {2} Divide 3, the coefficient of the x term, by 2 to get \frac {3} {2}X 2 3 x 7 = y Subtract y from both sides Subtract y from both sides x^ {2}3x7y=0 x 2 3 x 7 − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 3 for b, and 7y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}




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1 Answer 0 votes Given y = x^23x Compare it standard parabola equation y = ax^2bxc a = 1,b = 3, c = 0 Axis of symmetry is x = 3/2*1 = 3/2 Axis of symmetry is x = 3/2 Graph of y = x^23x answered by dozey MentorA) It will touch the xaxis when the polynomial has only one solution If the polynomial has only one solution, then the discriminant isAnswers 3 on a question At what point(s) do these graphs intersect?




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Y=x is a graph V shaped where the vertex of V is the origin So Now we will be doing origin shifting for y=x1 Say x1=X so y=X Now for y vs X graph, our graph will be a V with vertex of V at origin But Hey!Graph y=x^33x^22x Find the point at Tap for more steps Replace the variable with in the expression Simplify the result Tap for more steps Simplify each term Tap for more steps Raise to the power of Raise to the power of Multiply by Multiply by Simplify by subtracting numbersThe graph of the function g(x) has the same shape and direction of opening as the graph of f(x)= 3(x2)^29 The graph of g(x) has a vertex that is 2 units to the right and 5 units down from the vertex of the graph of f(x) A) math Given the minimum and maximum values of the function y=3sin(x)




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Is addition and one when it is subtraction x^ {2}3xy6=0 x 2 3 x − y − 6 = 0 This equation is in standard form ax^ {25 Consider the curve y = x^2 3x 2 (a) Sketch the curve over the range x = 0 to x = 3 (b) Evaluate the area bounded by the curve and the xaxis between the limits x=0 and x=1 Show your working ou read moreMultiply 4 4 by 1 1 Subtract 9 4 9 4 from 0 0 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x h) 2 k y = a ( x − h) 2 k, to determine the values of a a, h h, and k k



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Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutesSo this is a two stepper First you want to find the y value of the function at x = 2 When you substitute 2 for x, you should get 10 for y So now we know y(2) = 10 Then you need to find the slope of the tangent line which you can find by taking0 , and have a yintercept at (0,c) ( 0, c) By completing the




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Graph of the parabolas, y = x 2 (blue) and y = (1/4)x 2 (red) The general charactersitics of the value a, the coefficient When a is positive, the graph of y = ax 2 bx c opens upward and the vertex is the lowest point on the curve As the value ofQuestion Find yintercept and vertex y = x^2 3x 4 Answer by jim_thompson5910 () ( Show Source ) You can put this solution on YOUR website!Question for what value(s) of k will the graph of y = x^23xk a) touch the xaxis b) never meet the xaxis?




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Graph Drawn From The Equation Y X 2 3x 4 Will Be
√17 2 ← Exact solution As 17 is a prime number we can not simplify this any further Approximate solution x = − 15 ±Example 2 y = x 2 − 2 The only difference with the first graph that I drew (y = x 2) and this one (y = x 2 − 2) is the minus 2 The minus 2 means that all the yvalues for the graph need to be moved down by 2 units So we just take our first curve and move it down 2 units Our new curve's vertex is at −2 on the yaxisAnswer to Find the x and yintercepts of the graph of the equation y = x^2 3x 28 By signing up, you'll get thousands of stepbystep



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Question 3613 Find the xintercepts of the graph of the equations y = x^2 3x 2 y = x^2 1 Answer by ewatrrr () ( Show Source ) You can put this solution on YOUR website!Ex 32, 7 Draw the graphs of the equations x – y 1 = 0 and 3x 2y – 12 = 0 Determine the coordinates of the vertices of the triangle formed by these lines and the xaxis, and shade the triangular region Our equations are x – y = −1Graph and describe the rational function Taken from the Calc AB summer packet




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0 , downwards if a <B = −3 and c = 2 giving x = 3 ±Question 726 Graphing Y=x^23x2 Identify the vertext and the axis of symmetry Answer by jim_thompson5910 () ( Show Source ) You can put this solution on YOUR website!




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62 to 3 decimal places giving xintercept ≈ − 3562 and 0562 to 3 decimalSteps Using the Quadratic Formula y= \frac { { x }^ { 2 } 3x2 } { { x }^ { 2 } 1 } y = x 2 − 1 x 2 − 3 x 2 Variable x cannot be equal to any of the values 1,1 since division by zero is not defined Multiply both sides of the equation by \left (x1\right)\left (x1\right) Variable x cannot be equal to any of the values − 1, 1Hi, xintercepts are dtyermined when y = 0 x^2 3x 2 = 0



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We are given the curves {eq}\displaystyle y=2x^26x2x,\, y=x^23x4 {/eq}The graph of the this curves are shown below As shown in the graph,√( −3)2 − 4( − 1)( 2) 2( − 1) x = − 3 2 ±Algebra Graph y=2/3x1 y = − 2 3 x 1 y = 2 3 x 1 Rewrite in slopeintercept form Tap for more steps The slopeintercept form is y = m x b y = m x b, where m m is the slope and b b is the yintercept y = m x b y = m x b Write in y = m x b y = m x b form Tap for more steps



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B 2 − 4 a c The quadratic formula gives two solutions, one when ±Graph of Y=x^211x10 Below you can find the full step by step solution for you problem We hope it will be very helpful for you and it will help you to understand the solving process If it's not what You are looking for, type in into the box below your own function and let us find the graph of it The graph of Y=x^211x10 represents a graphGraph x^23x7 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola




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The graph of a general quadratic equation y= ax2bxc y = a x 2 b x c will open upwards if a >You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on will be the new center To reset the zoom to the original click on the Reset button Using a Values There is a slider with a = on it You can use a in your formula and then use the slider to change the value of aLearn the steps on how to graph y = 3x 2 by finding the yintercept and slope of the graph from the equationThe equation of the line must be in the form y



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Sign Now, we find where the dotted upward facingY= x^2 3x 18 We need to find the xintercept of the curve y The xintercept is the point where the curve y meets the xaxis Then the values of y would be zeroSolve by graphing y = x^2 3x 2 y = 2x 2 create a trigonometric function that describes the hours of sunlight for each day of the year d graph the function you build in part c e use the function you build in part c to find out how many fewer daylight hours february 10 will have than march 21 you may look at the calendar




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Y = ( −1)x2 −3x 2 So a = − 1;Click here 👆 to get an answer to your question ️ which point lies on the graph of the function shown below y=x^23x2 janyaluv999 janyaluv999 Mathematics Middle School answered Which point lies on the graph of the function shown below y=x^23x2 2Answer The x intercepts are (7,0) and (4,0) Stepbystep explanation y = x^2 – 3x 28 Set y=0 0 = x^2 – 3x 28 Factor What 2 numbers multiply to 28 and add to 3



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For y=ax^2bxc the x for vertex is x_v=b/(2a)=3/2 so y_v=x^2−3x8 = (3/2)^23*3/28= 23/4 So the vertex is ( 3/2,23/4) Since a>0, so it is looking up The yintercept is Y=0^23*08=8 so (0,8) After finding the yintercept, we should practically find the xintercept, but as you see, the graph is looking upward since a is bigger than 0 and the vertex is higher than 0 SoGraph the quadratic equation Find vertex, intercepts, axis of symmetry, etcThe easiest way to graph an equation in x and y (which will be a straight line) is to find two sets of values for x and y that satisfy this equation Putting 0 for x is easy y = 2 Now put in 1 for x y = 32 = 1 So two points that are on the line are at (0, 2) and (1, 1) The graph looks like this




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All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ±Draw the graph of y = x^2 3x – 4 and hence use it to solve x^2 3x – 4 = 0 y^2 = x 3x – 4 asked in Algebra by Darshee ( 491k points) algebra



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